Rate of change in angular momentum is equal to the torque on the rock.

$\overline{){\mathbf{\tau}}{\mathbf{=}}{\mathbf{r}}{\mathbf{\xb7}}{\mathbf{F}}{\mathbf{s}}{\mathbf{i}}{\mathbf{n}}{\mathbf{\theta}}}$

F = mg

θ = (90 - 36.9)

A 2.00-kg rock has a horizontal velocity of magnitude 12.0 m/s when it is at point P in the figure (Figure 1).

If the only force acting on the rock is its weight, what is the rate of change (magnitude and direction) of its angular momentum at this instant?

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Angular Momentum of Objects in Linear Motion concept. You can view video lessons to learn Angular Momentum of Objects in Linear Motion. Or if you need more Angular Momentum of Objects in Linear Motion practice, you can also practice Angular Momentum of Objects in Linear Motion practice problems.

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